Unit: Work, Energy, and Power

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When a mass is dropped from rest onto a vertical spring, mechanical energy is conserved, transforming among gravitational potential energy, elastic potential energy, and kinetic energy. Both gravity and the spring force do work on the mass as it falls and compresses the spring.

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Consider a mass mm dropped from rest at height hh above the natural length of a vertical spring with spring constant kk. Set the reference point y=0y = 0 at the natural length of the spring.

Phase 1: Dropping to Maximum Compression

Initially, the mass has gravitational potential energy Ug,i=mghU_{g,i} = mgh, zero kinetic energy, and zero elastic potential energy:

Ki=0K_i = 0 Ug,i=mghU_{g,i} = mgh Us,i=0U_{s,i} = 0
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(Note we are assuming a total energy of 100 J100\text{ J} for illustrative purposes here).

At maximum compression ymaxy_{\max} below the natural length, the mass momentarily stops, so Kf=0K_f = 0. The gravitational potential energy is Ug,f=mgymaxU_{g,f} = -mgy_{\max} (negative because the mass is below the reference), and the elastic potential energy is Us,f=12kymax2U_{s,f} = \frac{1}{2}ky_{\max}^2:

Kf=0K_f = 0 Ug,f=mgymaxU_{g,f} = -mgy_{\max} Us,f=12kymax2U_{s,f} = \frac{1}{2}ky_{\max}^2
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Applying conservation of mechanical energy:

Ei=EfE_i = E_f mgh=12kymax2mgymaxmgh = \frac{1}{2}ky_{\max}^2 - mgy_{\max}

Rearranging into standard quadratic form:

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... continued in the full lesson.

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