Unit: Torque and Rotational Dynamics

Prerequisites

Later Topics

None

Multi-Step Problem Preview

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Part 1

A spool of mass MM has an inner hub of radius rr and an outer rim of radius RR. It rests on a rough horizontal surface where the coefficient of static friction is μs\mu_s. A string is wrapped around the inner hub (underneath) and pulled with a force FF at some angle θ\theta with respect to the horizontal.

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When the string is pulled horizontally (θ=0\theta = 0), the tension FF exerts a counter-clockwise torque FrF r about the center of the spool. However, the spool is observed to roll to the right (clockwise rotation).

Which force is responsible for producing the clockwise torque about the center that causes this motion?

Correct!

Solution:

The spool experiences gravity MgMg acting downward at the center, the applied tension FF pulling horizontally to the right at radius rr (under the hub), the normal force from the ground, and static friction fsf_s at the contact point.

Compute torques about the center of the spool.

The tension FF acts at a perpendicular lever arm rr, producing a counter-clockwise torque of magnitude FrF r.

Gravity MgMg acts through the center, so its torque about the center is 00.

The normal force acts at the contact point directly below the center, so its line of action passes through the center and its torque about the center is also 00.

Static friction fsf_s acts at the contact point, a distance RR from the center. If the spool rolls to the right with clockwise rotation, the friction force must act to the left at the bottom. A leftward force applied at the bottom produces a clockwise torque of magnitude fsRf_s R about the center.

Therefore, the force responsible for producing the clockwise torque about the center is static friction.

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