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An object placed in a fluid either floats or sinks. We can predict which by comparing densities.

Force Analysis

Consider an object of volume VV and density ρobj\rho_{\text{obj}} fully submerged in a fluid of density ρfluid\rho_{\text{fluid}}. Two forces act vertically: weight WW downward and buoyant force FBF_B upward.

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From Archimedes' principle:

FB=ρfluidVgF_B = \rho_{\text{fluid}} \cdot V \cdot g

The weight of the object is:

W=ρobjVgW = \rho_{\text{obj}} \cdot V \cdot g

Applying Newton's second law in the vertical direction (taking upward as positive):

Fnet=FBWF_{\text{net}} = F_B - W Fnet=ρfluidVgρobjVgF_{\text{net}} = \rho_{\text{fluid}} \cdot V \cdot g - \rho_{\text{obj}} \cdot V \cdot g Fnet=Vg(ρfluidρobj)F_{\text{net}} = V \cdot g \cdot (\rho_{\text{fluid}} - \rho_{\text{obj}})

The Density Criterion

The net force direction depends entirely on which density is larger.

When ρobj<ρfluid\rho_{\text{obj}} < \rho_{\text{fluid}}, the net force is positive (upward). The object rises and floats.

When ρobj>ρfluid\rho_{\text{obj}} > \rho_{\text{fluid}}, the net force is negative (downward). The object sinks.

When ρobj=ρfluid\rho_{\text{obj}} = \rho_{\text{fluid}}, the net force is zero. The object has neutral buoyancy and remains at any depth.

... continued in the full lesson.

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