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When an object is submerged in a fluid, the fluid exerts pressure on all surfaces. Since pressure increases with depth (P=P0+ρghP = P_0 + \rho g h), the bottom of the object experiences greater pressure than the top. This pressure difference produces a net upward force called the buoyant force FBF_B.

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Consider a submerged object of height \ell with horizontal top and bottom surfaces of area AA. Let the top surface be at depth h1h_1 and the bottom at depth h2=h1+h_2 = h_1 + \ell. The pressures are:

Ptop=P0+ρfluidgh1P_{\text{top}} = P_0 + \rho_{\text{fluid}} g h_1 Pbottom=P0+ρfluidgh2P_{\text{bottom}} = P_0 + \rho_{\text{fluid}} g h_2

The upward force from below exceeds the downward force from above. The net buoyant force is:

FB=PbottomAPtopAF_B = P_{\text{bottom}} A - P_{\text{top}} A FB=ρfluidg(h2h1)A=ρfluidgAF_B = \rho_{\text{fluid}} g (h_2 - h_1) A = \rho_{\text{fluid}} g \ell A

The product A\ell A equals the volume VV of fluid displaced by the object.

... continued in the full lesson.

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