Unit: 1D Kinematics

Prerequisites

Later Topics

Lesson Preview

When an object undergoes multiple movements in sequence, we find its total displacement by adding the individual displacements together.

For horizontal motion with displacements Δx1\Delta x_1, Δx2\Delta x_2, Δx3\Delta x_3, etc., the total displacement is:

Δxtotal=Δx1+Δx2+Δx3+\Delta x_{total} = \Delta x_1 + \Delta x_2 + \Delta x_3 + \cdots

Positive values represent rightward movement and negative values represent leftward movement. For example, if an object moves right by Δx1=5 m\Delta x_1 = 5 \text{ m} , left by Δx2=3 m\Delta x_2 = -3 \text{ m} , then right by Δx3=2 m\Delta x_3 = 2 \text{ m} :

Loading visualization…

The total displacement is:

Δxtotal=5+(3)+2=4 m\Delta x_{total} = 5 + (-3) + 2 = 4 \text{ m}

For vertical motion with displacements Δy1\Delta y_1, Δy2\Delta y_2, Δy3\Delta y_3, etc.:

Δytotal=Δy1+Δy2+Δy3+\Delta y_{total} = \Delta y_1 + \Delta y_2 + \Delta y_3 + \cdots

Positive values represent upward movement and negative values represent downward movement. If an object moves up by Δy1=8 m\Delta y_1 = 8 \text{ m} , down by Δy2=5 m\Delta y_2 = -5 \text{ m} , down by Δy3=2 m\Delta y_3 = -2 \text{ m} , then up by Δy4=3 m\Delta y_4 = 3 \text{ m} :

... continued in the full lesson.

Ready to Start Learning?

Sign up now to access the full Multi-step Displacement lesson and our entire curriculum!