Unit: Work, Energy, and Power

Lesson Preview

When you lift an object of mass mm through a vertical height hh in Earth's gravitational field, you do work against the gravitational force. This work is stored as gravitational potential energy in the object-Earth system.

Derivation from Work:

Consider lifting an object of mass mm slowly at constant velocity from a reference level (where we define Ug=0U_g = 0, more on this later) to height hh above that level.

The gravitational force on the object has magnitude:

Fg=mgF_g = mg

This force acts downward. To lift the object at constant velocity, you must apply an upward force equal in magnitude to the gravitational force. The displacement is upward through distance hh.

Since the applied force and displacement are in the same direction, the work you do is:

Wapplied=Fappliedh=mghW_{\text{applied}} = F_{\text{applied}} \cdot h = mgh
Compiling TikZ diagram...

This work is stored as gravitational potential energy in the system:

Ug=mghU_g = mgh

Here g9.8 m/s2g \approx 9.8~\text{m/s}^2 near Earth's surface, and hh is measured from the chosen reference level.

...

... continued in the full lesson.

Ready to Start Learning?

Sign up now to access the full Gravitational Potential Energy lesson and our entire curriculum!