Unit: Linear Momentum

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Explosions and recoil events involve internal forces that push system components apart. According to Newton's Third Law, these internal forces occur in action-reaction pairs that sum to zero, leaving the total linear momentum of the system unchanged. Provided that external forces are negligible compared to interaction forces, the system is approximately isolated during the event and momentum is conserved.

Kinetic energy, however, is not conserved in explosions and recoil. Instead, internal energy from explosives or springs are converted to kinetic energy.

Consider a cannon of mass mcm_c containing a projectile of mass mpm_p. Initially, both components are at rest, so the total initial momentum Pi\vec{P}_i is zero:

Pi=0\vec{P}_i = 0

Upon firing, the projectile launches with velocity vp\vec{v}_p and the cannon recoils with velocity vc\vec{v}_c. The final total momentum Pf\vec{P}_f is the vector sum of the individual momenta:

Pf=mcvc+mpvp\vec{P}_f = m_c \vec{v}_c + m_p \vec{v}_p

Applying the conservation of momentum Pf=Pi\vec{P}_f = \vec{P}_i yields:

mcvc+mpvp=0m_c \vec{v}_c + m_p \vec{v}_p = 0

Rearranging this equation relates the recoil momentum to the projectile momentum:

mcvc=mpvpm_c \vec{v}_c = -m_p \vec{v}_p

This result demonstrates that the momentum of the cannon is equal in magnitude and opposite in direction to the momentum of the projectile. Since the cannon mass mcm_c is typically much larger than the projectile mass mpm_p, the recoil speed vc|\vec{v}_c| is significantly smaller than the projectile speed vp|\vec{v}_p|.

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