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We've worked with nn-dimensional vectors in Rn\mathbb{R}^n

What if we allow the entries of an nn-dimensional vector to be complex? That is:

v=[v1v2vn]\vec{v} = \begin{bmatrix} v_1 \\ v_2 \\ \vdots \\ v_n \end{bmatrix}

where each viCv_i \in \mathbb{C}, i.e., each viv_i is a complex number.

Note: This includes the case where the viv_i are real since real numbers are a subset of complex numbers (RC)\left( \mathbb{R} \subset \mathbb{C}\right).

For example:

[13i1+2i],[1+3i22i2],etc...\begin{bmatrix} 1 - 3i \\ 1 + 2i \end{bmatrix}, \quad \begin{bmatrix} 1 + 3i \\ 2 - \sqrt{2}i \\ 2 \end{bmatrix}, \quad \text{etc...}

No problem! We can let the scalars that we multiply the vectors by also be complex  as well i.e., cvc\vec{v}, where cCc \in \mathbb{C}.

All our ideas around addition, subtraction, and scalar multiplication that we've learned for Rn\mathbb{R}^n carry over.

We call the set of all nn-dimensional vectors with complex entries Cn\mathbb{C}^n.

So:

... ...

... continued in the full lesson.

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