Lesson Preview

Bernoulli's equation expresses conservation of energy per unit volume for an ideal fluid flowing along a streamline.

Consider a fluid element of volume VV and mass m=ρVm = \rho V. This element has kinetic energy 12mv2\frac{1}{2}mv^2 and gravitational potential energy mghmgh. Dividing by volume gives energy densities:

Kinetic energy density=12ρv2\text{Kinetic energy density} = \frac{1}{2}\rho v^2 Gravitational potential energy density=ρgh\text{Gravitational potential energy density} = \rho g h

Pressure PP has units of Pa=N/m2=J/m3\text{Pa} = \text{N/m}^2 = \text{J/m}^3, which is energy per unit volume. It represents work done by pressure forces per unit volume.

Bernoulli's equation states that the total energy density is constant along a streamline:

P+12ρv2+ρgh=constantP + \frac{1}{2}\rho v^2 + \rho g h = \text{constant}

For two points along the same streamline:

P1+12ρv12+ρgh1=P2+12ρv22+ρgh2P_1 + \frac{1}{2}\rho v_1^2 + \rho g h_1 = P_2 + \frac{1}{2}\rho v_2^2 + \rho g h_2

This unifies ideas you already know. The continuity equation relates speed to cross-sectional area. Hydrostatic pressure describes ρgh\rho g h for fluids at rest. Bernoulli's equation extends these to moving fluids: when speed increases, pressure or height must decrease to keep the sum constant.

... continued in the full lesson.

Ready to Start Learning?

Sign up now to access the full Bernoulli's Equation lesson and our entire curriculum!