Unit: Fluids

Lesson Preview

When fluid flows through a narrowing pipe, the continuity equation A1v1=A2v2A_1 v_1 = A_2 v_2 requires the speed to increase. Bernoulli's equation then demands that pressure decrease to conserve energy density. This inverse relationship between speed and pressure is the Venturi effect.

For a horizontal pipe, Bernoulli's equation gives:

P1+12ρv12=P2+12ρv22P_1 + \frac{1}{2}\rho v_1^2 = P_2 + \frac{1}{2}\rho v_2^2

The pressure drop is:

ΔP=P1P2=12ρ(v22v12)\Delta P = P_1 - P_2 = \frac{1}{2}\rho(v_2^2 - v_1^2)

... continued in the full lesson.

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