Unit: 1D Kinematics

Prerequisites

Later Topics

None

Multi-Step Problem Preview

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Part 1

A police car is sitting still (vi=0v_{i} = 0), when another car goes by at 27 m/s27\text{ m/s}.

In the police car's reference frame, what is the initial velocity of the car relative to the police vrel,iv_{rel, i}?

Correct!

Solution:

The relative velocity of the car with respect to the police, vrelv_{rel}, is the velocity of the car, vcarv_{car}, minus the velocity of the police car, vpolicev_{police}.

vrel=vcarvpolicev_{rel} = v_{car} - v_{police}

The problem asks for the initial relative velocity at the moment the car passed the police. At this instant, the car is moving at its constant velocity, vcarv_{car}. The police car is at rest, so its initial velocity is vpolice,i=0 m/sv_{police,i} = 0 \text{ m/s}.

Substituting these initial values into the relative velocity equation gives:

vrel,i=vcarvpolice,i=vcar0=vcarv_{rel, i} = v_{car} - v_{police, i} = v_{car} - 0 = v_{car}

vrel,i=27 m/sv_{rel, i} = 27 \text{ m/s}

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