Unit: Energy and Momentum of Rotating Systems

Prerequisites

Later Topics

None

Lesson Preview

From constant to variable torque

For a constant torque τ\tau, the work done over an angular displacement Δθ\Delta\theta is:

W=τΔθW = \tau \cdot \Delta\theta

On a graph of torque versus angular position, this product equals the area of the rectangle formed between the horizontal torque line and the θ\theta-axis. The base of the rectangle is Δθ\Delta\theta, and the height is τ\tau.

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When torque varies with angular position, the same principle applies: work equals the area under the torque versus angular position curve. This generalizes the constant-torque formula to any torque function.

Dimensional check: The horizontal axis has units of radians (dimensionless) and the vertical axis has units of Nm\text{N} \cdot \text{m}. The product (Nm)(rad)=Nm=J(\text{N} \cdot \text{m}) \cdot (\text{rad}) =\text{N} \cdot \text{m}= \text{J}, confirming that area gives work.

Sign conventions: Regions where τ>0\tau > 0 (above the axis) contribute positive work—energy enters the system. Regions where τ<0\tau < 0 (below the axis) contribute negative work—energy leaves the system. The total work is the algebraic sum of all signed areas.

Decomposing piecewise-linear graphs

Break the region under the curve into rectangles, triangles, and trapezoids.

Rectangle: When torque is constant over an interval,

A=τ0ΔθA = \tau_0 \cdot \Delta\theta
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Triangle: When torque changes linearly from zero (or to zero),

A=12ΔθΔτA = \frac{1}{2} \cdot \Delta\theta \cdot \Delta\tau

... continued in the full lesson.

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