Unit: Linear Momentum

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Part 1

A dart of mass mdartm_{\mathrm{dart}} is thrown to the right with horizontal velocity vdartv_{\mathrm{dart}} at a stationary cart of mass mcartm_{\mathrm{cart}}.

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Which object or system receives a net negative horizontal impulse during the collision? Take motion to the right as positive.

Correct!

Solution:

Let the positive horizontal direction be defined to the right. The impulse JJ acting on an object is strictly equal to its change in momentum Δp\Delta p. We analyze the momentum change for the dart:

Jdart=Δpdart=mdart(vf,dartvi,dart) J_{\mathrm{dart}} = \Delta p_{\mathrm{dart}} = m_{\mathrm{dart}} \cdot (v_{f,\mathrm{dart}} - v_{i,\mathrm{dart}})

The dart is initially traveling to the right, so vi,dart=vdart>0v_{i,\mathrm{dart}} = v_{\mathrm{dart}} > 0. During the collision, the dart exerts a force on the cart to the right, and by Newton's third law, the cart exerts a force on the dart to the left. This force opposes the motion, causing the dart to slow down or rebound. In either case, the final velocity vf,dartv_{f,\mathrm{dart}} is algebraically less than the initial velocity vdartv_{\mathrm{dart}}:

vf,dart<vdart v_{f,\mathrm{dart}} < v_{\mathrm{dart}}

Substituting this inequality into the impulse equation:

Jdart=mdart(vf,dartvdart)<0 J_{\mathrm{dart}} = m_{\mathrm{dart}} \cdot (v_{f,\mathrm{dart}} - v_{\mathrm{dart}}) < 0

Thus, the dart receives a net negative horizontal impulse. The cart, starting from rest and gaining velocity to the right, receives a positive impulse. The combined system experiences zero net impulse given no external horizontal forces.

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